Revision ecabe27e

b/lib/utils/text.py
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      num_b = len(e1) - len(e1.rstrip("\\"))
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      if num_b % 2 == 1 and slist:
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        e2 = slist.pop(0)
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        # here the backslashes remain (all), and will be reduced in
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        # the next step
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        rlist.append(e1 + sep + e2)
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        # Merge the two elements and push the result back to the source list for
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        # revisiting. If e2 ended with backslashes, further merging may need to
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        # be done.
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        slist.insert(0, e1 + sep + e2)
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        continue
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    # here the backslashes remain (all), and will be reduced in the next step
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    rlist.append(e1)
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  # finally, replace backslash-something with something
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  rlist = [re.sub(r"\\(.)", r"\1", v) for v in rlist]

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